8u^2+3u-2=0

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Solution for 8u^2+3u-2=0 equation: 



8u^2+3u-2=0

a = 8; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·8·(-2)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{73}}{2*8}=\frac{-3-\sqrt{73}}{16}
$


$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{73}}{2*8}=\frac{-3+\sqrt{73}}{16}
$

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